Write a polite but firm email to a landlord who has not fixed the heating for three weeks. I want the repair, not a fight.
Muse Spark Open
Here is a polite but firm template you can copy, paste and customize. It's designed to get the repair done while keeping the relationship professional:
Subject: Follow-up: Heating repair request at [Your Address / Apt #] - Outstanding 3 weeks
Dear [Mr./Ms. Last Name],
I hope you are well. I am writing to follow up regarding the heating issue at [Your Full Address, Apt #].
I first reported that the heating was not working on [Date of first report - e.g., January 20, 2026], and have followed up on [Date of 2nd contact] and [Date of 3rd contact]. As of today, it has now been three weeks without functioning heat.
With the cold weather, this is becoming difficult to live with, and I would like to get this resolved as soon as possible.
Could you please arrange for a qualified technician to repair the heating by [Give a reasonable, specific deadline - e.g., Friday, February 13]? I am available for access on [List 2-3 dates/times you are available, e.g., weekday afternoons after 3pm and anytime Thursday/Friday] but I am happy to adjust if another time works better for your contractor.
Please could you let me know in writing what the plan and timeline for the repair will be? I appreciate that repairs can take time to coordinate, and I want to work with you to get this sorted.
Thank you very much for your help with this. I look forward to your reply.
Kind regards, [Your Full Name] [Your Address / Apt #] [Your Phone Number]
Tips to make it effective:
Keep a record: Send it by email and keep a copy. Note the dates you reported it previously.
Give a clear deadline: 3-5 business days is usually considered reasonable and firm.
Offer access: Landlords often delay because they say they couldn't get in. Offering times removes that barrier.
Stay solution-focused: The tone here is "we both want this fixed" rather than accusatory.
If you get no response after your deadline, you can add this one sentence in a follow-up: "As heating is considered an essential service, I want to resolve this directly with you before I look into other options for advice and support."
Want me to tailor this with your exact dates, address, and landlord's name?
Asked Nov 1, 2026. Unedited.
Write a React hook that debounces a value and cancels on unmount. Include the TypeScript types.
Muse Spark Open
This hook debounces any value and automatically cancels the pending timeout on unmount via useEffect cleanup:
import { useState, useEffect } from 'react';
export function useDebounce<T>(value: T, delay: number): T {
const [debouncedValue, setDebouncedValue] = useState<T>(value);
useEffect(() => {
// Set a timer to update the debounced value after the delay
const timerId = setTimeout(() => {
setDebouncedValue(value);
}, delay);
// Cleanup: cancels pending update on value/delay change or on unmount
return () => {
clearTimeout(timerId);
};
}, [value, delay]);
return debouncedValue;
}Usage
import { useState } from 'react';
import { useDebounce } from './useDebounce';
function SearchInput() {
const [query, setQuery] = useState<string>('');
const debouncedQuery = useDebounce<string>(query, 500);
// This effect only fires after user stops typing for 500ms
useEffect(() => {
if (debouncedQuery) {
// fetchResults(debouncedQuery)
}
}, [debouncedQuery]);
return (
<input
value={query}
onChange={(e) => setQuery(e.target.value)}
placeholder="Search..."
/>
);
}The
return () => clearTimeout(timerId)insideuseEffectguarantees no state update is attempted after the component unmounts or ifvaluechanges beforedelayexpires.
Asked Nov 1, 2026. Unedited.
A drug test is 99% accurate, and 0.5% of people use the drug. Someone tests positive. What is the probability they use it, and why does the answer surprise people?
Muse Spark Open
This is a classic Bayes' Theorem problem. The answer is about 33%, not 99%.
Let:
D= you use the drug+= you test positive
We are given:
P(D) = 0.5% = 0.005->P(not D) = 0.995P(+|D) = 99% = 0.99: If you do use, you test positive 99% of the time (sensitivity)P(not +|not D) = 99% = 0.99: If you don't use, you test negative 99% of the time (specificity)
Which means: P(+|not D) = 1% = 0.01 : False positive rate
You want P(D|+) - if you tested positive, what is the chance you actually use?
People confuse
P(+|D)withP(D|+). The test is 99% accurate when we know you use. We don't know the reverse.
By Bayes' Theorem:
$$P(D|+) = \frac{P(+|D) \cdot P(D)}{P(+)}$$
$$P(+) = P(+|D)P(D) + P(+|not D)P(not D)$$
$$P(+) = 0.99 \times 0.005 + 0.01 \times 0.995$$ $$P(+) = 0.00495 + 0.00995 = 0.0149$$
So:
$$P(D|+) = \frac{0.00495}{0.0149} \approx 0.332 = 33.2\%$$
If you test positive, there's only about a 1 in 3 chance you actually use the drug.
Why it's so surprising: The Base Rate Fallacy
Think in natural frequencies instead of percentages. Imagine 10,000 people:
50 are users (0.5%): 99% test positive -> ~49 true positives
9,950 are non-users: 1% test positive -> ~100 false positives
Total positives: 49 + 100 = 149
True users among positives: 49 / 149 ≈ 33%
Our brain does two things wrong:
1. We ignore the base rate. 0.5% is extremely rare. There are ~200x more non-users than users. Even a tiny 1% error rate on that huge group of non-users creates twice as many false positives as there are real positives.
2. We confuse the conditional. We hear "99% accurate" and think it means P(user | positive) = 99%. It doesn't. It means P(positive | user) = 99%.
This is why doctors don't panic at a single positive result for a rare disease, and why a second independent test is so powerful. If you tested positive twice in a row, the updated probability jumps to ~98%.
Asked Nov 1, 2026. Unedited.
What it’s good at
Ranked against 42 models, from public leaderboards and our own blind tests where we have them. How we rank
- #19of 42 for coding
- #19of 42 for research
- #20of 42 for math
The facts
Muse Spark Open is a Muse Spark model from Meta. It takes images, audio and video as well as text.
Scores from artificialanalysis.ai and lmarena.ai.
- Made by
- Meta
- API price, per 1M tokens
- $1.25 in, $4.25 out
- Speed
- No public score
- Artificial Analysis Index
- No public score
- LMArena text
- No public score
- LMArena coding
- No public score
- Updated
- Oct 26, 2026