Write a polite but firm email to a landlord who has not fixed the heating for three weeks. I want the repair, not a fight.
Gemini 3.5 Flash Lite
Subject: URGENT: Ongoing Heating Issue at [Your Apartment Number] — Request for Immediate Repair
Dear [Landlord's Name],
I hope you are having a good week.
I am writing to follow up once again regarding the lack of heating in the apartment. As you know, this issue has now been ongoing for three weeks, since [Insert Date, e.g., November 4th].
While I understand that unexpected maintenance issues can be complicated, living without heat for this length of time is becoming increasingly difficult and impacts the livability of the home.
My goal is simply to get the heating working properly so we can resolve this smoothly. Could you please confirm today when a technician will be sent to complete the permanent repair?
Thank you for your prompt attention to this matter. I look forward to hearing from you with a concrete timeline today.
Best regards,
[Your Name] [Your Apartment Number] [Your Phone Number]
Asked Nov 1, 2026. Unedited.
Write a React hook that debounces a value and cancels on unmount. Include the TypeScript types.
Gemini 3.5 Flash Lite
Here is a clean, fully typed React hook for debouncing a value that automatically cancels any pending timeouts when the component unmounts.
The Hook: useDebounce
import { useState, useEffect } from 'react';
/**
* Custom hook that debounces a value.
*
* @param value - The value to debounce.
* @param delay - The delay in milliseconds.
* @returns The debounced value.
*/
export function useDebounce<T>(value: T, delay: number): T {
const [debouncedValue, setDebouncedValue] = useState<T>(value);
useEffect(() => {
// Set up a timer to update the debounced value after the specified delay
const timer = setTimeout(() => {
setDebouncedValue(value);
}, delay);
// Clean up the timeout if the value changes (re-running effect)
// or if the component unmounts. This naturally cancels the debounce.
return () => {
clearTimeout(timer);
};
}, [value, delay]);
return debouncedValue;
}Example Usage
Here is how you might use it in a search component:
import React, { useState } from 'react';
import { useDebounce } from './useDebounce';
export function SearchComponent() {
const [searchTerm, setSearchTerm] = useState('');
// Debounce the search term by 500ms
const debouncedSearchTerm = useDebounce(searchTerm, 500);
// You can perform your API call inside an effect tied to the debounced value
React.useEffect(() => {
if (debouncedSearchTerm) {
console.log('Fetching API for:', debouncedSearchTerm);
// fetchSearchResults(debouncedSearchTerm);
}
}, [debouncedSearchTerm]);
return (
<div>
<input
type="text"
value={searchTerm}
onChange={(e) => setSearchTerm(e.target.value)}
placeholder="Search..."
/>
<p>Current value: {searchTerm}</p>
<p>Debounced value: {debouncedSearchTerm}</p>
</div>
);
}Why this works:
Generics (
<T>): The hook accepts any data type (strings, numbers, objects, arrays) and preserves that exact type for the returned debounced value.Cleanup Function: React runs the function returned by
useEffectwhenever the effect dependencies change or when the component unmounts. CallingclearTimeout(timer)inside this cleanup prevents state updates on unmounted components and cancels the pending debounce if a new value comes in.
Asked Nov 1, 2026. Unedited.
A drug test is 99% accurate, and 0.5% of people use the drug. Someone tests positive. What is the probability they use it, and why does the answer surprise people?
Gemini 3.5 Flash Lite
Based on Bayes' Theorem, the probability that a person who tests positive actually uses the drug is approximately 33% (or about 1 in 3).
Here is the step-by-step math, followed by why this result catches almost everyone off guard.
The Math (Using a Sample of 10,000 People)
Imagine a population of 10,000 people.
How many actually use the drug? At 0.5%, that is $0.5\%$ of $10,000 = \mathbf{50\text{ people}}$.
How many do NOT use the drug? The remaining people: $10,000 - 50 = \mathbf{9,950\text{ people}}$.
Now, let's apply the 99% accuracy rate (assuming a 1% false positive and 1% false negative rate for simplicity):
True Positives (Users who test positive): $99\%$ of the 50 users $= \mathbf{49.5\text{ people}}$.
False Positives (Non-users who test positive): $1\%$ (the error rate) of the 9,950 non-users $= \mathbf{99.5\text{ people}}$.
Total Positive Tests: $49.5\text{ (true positives)} + 99.5\text{ (false positives)} = \mathbf{149\text{ total positive tests}}$.
Finally, what is the probability that someone who tested positive is actually a user? $$\frac{\text{True Positives}}{\text{Total Positives}} = \frac{49.5}{149} \approx \mathbf{33.2\%}$$
Why Does This Surprise People?
This is a classic example of Base Rate Fallacy and intuitive statistical blindness. People are surprised for a few psychological and logical reasons:
We focus on the test, not the baseline: When we hear "99% accurate," our brains anchor to that high number. We assume a positive test is practically a smoking gun. We forget to factor in how rare the condition is in the general population.
False positives overwhelm true positives: Because the drug is so rare (only 50 users out of 10,000), the number of healthy people who accidentally test positive (99.5) is actually twice as large as the number of actual users who test positive (49.5). Therefore, a random positive test is statistically much more likely to be a false alarm than a true hit.
Linear intuition vs. Conditional probability: Humans are not naturally wired to calculate conditional probabilities on the fly. We tend to think, "If the test is right 99% of the time, then a positive result means a 99% chance."
This exact mathematical counter-intuition applies not just to drug tests, but also to medical screenings (like mammograms or rare disease testing) and spam filters.
Asked Nov 1, 2026. Unedited.
What it’s good at
Ranked against 42 models, from public leaderboards and our own blind tests where we have them. How we rank
- #37of 42 for writing
- #38of 42 for research
- #39of 42 for coding
The facts
Gemini 3.5 Flash Lite is the lightest model in Google’s Gemini 3.5 family. It reads text, images, PDFs and video.
Scores from artificialanalysis.ai and lmarena.ai.
- Made by
- API price, per 1M tokens
- $0.30 in, $2.50 out
- Speed
- 419 tokens a second
- Artificial Analysis Index
- 22.2
- LMArena text
- 1,435
- LMArena coding
- 1,453
- Updated
- Oct 26, 2026